- Joined
- Feb 19, 2018
- Messages
- 31
When I rewrote my Easy Math Challenge in Cerberus X, I also implemented these easy String functions. There're easy to implement, but if you haven't implemented them, you might think in your project alternative ways to implement something, which in some cases might be more complicated. Any way here they are:
Example usage directly form Easy Math Challenge:
Code:
Method mid:String(str:String, startPos:Int, howMany:Int)
Return str[(startPos)..(startPos+howMany)]
End
Method left:String(str:String, howMany:Int)
Return str[0..howMany]
End
Method right:String(str:String, howMany:Int)
Return str[(str.Length()-howMany)..(str.Length())]
End
Example usage directly form Easy Math Challenge:
- mid(scrollText,charCounter,1)
- left(actualVPuzzle,1)
Last edited: