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Snippet Left, Mid & Right functions for Cerberus X

AutmnLeaf

New member
Tutorial Author
Joined
Feb 19, 2018
Messages
31
When I rewrote my Easy Math Challenge in Cerberus X, I also implemented these easy String functions. There're easy to implement, but if you haven't implemented them, you might think in your project alternative ways to implement something, which in some cases might be more complicated. Any way here they are:

Code:
    Method mid:String(str:String, startPos:Int, howMany:Int)
  
        Return str[(startPos)..(startPos+howMany)]
    End

    Method left:String(str:String, howMany:Int)
  
        Return str[0..howMany]
    End
  
    Method right:String(str:String, howMany:Int) 
        Return str[(str.Length()-howMany)..(str.Length())]
    End

Example usage directly form Easy Math Challenge:
  • mid(scrollText,charCounter,1)
  • left(actualVPuzzle,1)
You'll get the idea. :)
 
Last edited:
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